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Hello,
I have the formula but would like to add the IfError to it to avoid the #DIVIDE BY ZERO - any suggestions?
=[2018/2019 Sales]1 / [Square Feet]1
Try this.
=IFERROR([2018/2019 Sales]1 / [Square Feet]1, 0)
On my sheet, I have a Planned Migration Date column that has discrete date values for each row. I have another column called "Migration Week Monday" where it determines Monday's date for the associated Planned Migration Date. My formula works well on the sheet up until I use a cross sheet formula to pull in the date value,…
Hello all. I've searched for a solution but have not found one. I am using an index match formula to return an "employee name" based on a "project name" match. The formula returns no match…but there should be. Scenario: I have a sheet which lists projects including: project #, project name, super, etc. I used a formula on…
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