Find previous date for then calculate days between dates
Hi all,
I'm having difficulty creating a column that shows the number of days between jobs at the specific venue.
Sheet is essentially a list of jobs at various venues.
VENUE A, 02/02/23
VENUE B, 10/02/23
VENUE C, 15/02/23
VENUE A, 16/02/23
The column I'd like to create would show the last row for VENUE A as 14 days.
I'd prefer to be able to create a column formula, which means I can set and forget. I have no issue creating multiple helper columns and I have a master file in another sheet that could be used.
A potential problem is there is full year of jobs listed, but the purpose is to be able to know the new gap between jobs when changing a date and I don't want to alter the future planning on the sheet.
Thanks
Ryan
Best Answer
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If I am understanding right this should work.
Last Job =MAX(COLLECT([Job Date]:[Job Date], [Job Date]:[Job Date], MAX(COLLECT([Job Date]:[Job Date], Venue:Venue, Venue@row, [Job Date]:[Job Date], <[Job Date]@row, Venue:Venue, Venue@row))))
Days Since Previous Job =IFERROR(NETDAYS([Last Job]@row, [Job Date]@row), "First Job")
Nested into a single formula
Day Since Previous Job =IFERROR(NETDAYS(MAX(COLLECT([Job Date]:[Job Date], [Job Date]:[Job Date], MAX(COLLECT([Job Date]:[Job Date], Venue:Venue, Venue@row, [Job Date]:[Job Date], <[Job Date]@row, Venue:Venue, Venue@row)))), [Job Date]@row), "First Job")
Answers
-
If I am understanding right this should work.
Last Job =MAX(COLLECT([Job Date]:[Job Date], [Job Date]:[Job Date], MAX(COLLECT([Job Date]:[Job Date], Venue:Venue, Venue@row, [Job Date]:[Job Date], <[Job Date]@row, Venue:Venue, Venue@row))))
Days Since Previous Job =IFERROR(NETDAYS([Last Job]@row, [Job Date]@row), "First Job")
Nested into a single formula
Day Since Previous Job =IFERROR(NETDAYS(MAX(COLLECT([Job Date]:[Job Date], [Job Date]:[Job Date], MAX(COLLECT([Job Date]:[Job Date], Venue:Venue, Venue@row, [Job Date]:[Job Date], <[Job Date]@row, Venue:Venue, Venue@row)))), [Job Date]@row), "First Job")
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Thanks for your help. Problem solved!
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