Can't get formula to work

All columns are in one sheet

Column A - value

Column B - status - a selection of drop downs

Column C - owners - a selection of drop downs

Hi I'm looking to extract the sum of values in Column A (£s) based on matches of data in column B (a selection of 6 out of 8 status) & C - a single select owner

I have a worksheet set up so the formula in the cell would look up another single worksheet

Help

Best Answer

  • KPH
    KPH ✭✭✭✭✭✭
    Answer ✓

    You could use a SUMIFS function. In it's simplest form SUMIFS just requires a range to sum (your column A) and a criteria range (for example column C) and a criterion (for example the owner).

    If this was your data

    The formula

    =SUMIFS(Value:Value, Owners:Owners, "Pluto")

    Would give you 846. This is the sum of the two rows owned by Pluto.

    You can extend this and add a second criterion range and criteria. For example:

    =SUMIFS(Value:Value, Owners:Owners, "Pluto", Status:Status, "Testing")

    This would give you 346. Only the row owned by Pluto that has the status of "Testing".

    To put this formula on in a separate sheet to the data you replace the ranges with the cross sheet references you set up. The formula would then look something like (reference names will vary):

    =SUMIFS({value}, {owners}, "Pluto", {status}, "Testing")

    Things are complicated if your drop downs allow multi-select or are contact type. I am going to assume they are not.

    If you have 8 possible things in the Status column and want to sum 6 of them, you can add an OR function to the criteria and list the 6 that you want to include like this:

    =SUMIFS(Value:Value, Owners:Owners, "Mickey", Status:Status, OR(@cell = "Testing", @cell = "Not started", @cell = "Requirements capture", @cell = "Completed", @cell = "In development", @cell = "Billing"))
    

    In my example, this would return 255,703.

    Alternatively, you could write a shorter formula to count rows where the status is not the 2 you don't want.

    =SUMIFS(Value:Value, Owners:Owners, "Mickey", Status:Status, AND(@cell <> "Cancelled", @cell <> "On Hold"))
    

    In my example, this would still return 255,703.

Answers

  • KPH
    KPH ✭✭✭✭✭✭
    Answer ✓

    You could use a SUMIFS function. In it's simplest form SUMIFS just requires a range to sum (your column A) and a criteria range (for example column C) and a criterion (for example the owner).

    If this was your data

    The formula

    =SUMIFS(Value:Value, Owners:Owners, "Pluto")

    Would give you 846. This is the sum of the two rows owned by Pluto.

    You can extend this and add a second criterion range and criteria. For example:

    =SUMIFS(Value:Value, Owners:Owners, "Pluto", Status:Status, "Testing")

    This would give you 346. Only the row owned by Pluto that has the status of "Testing".

    To put this formula on in a separate sheet to the data you replace the ranges with the cross sheet references you set up. The formula would then look something like (reference names will vary):

    =SUMIFS({value}, {owners}, "Pluto", {status}, "Testing")

    Things are complicated if your drop downs allow multi-select or are contact type. I am going to assume they are not.

    If you have 8 possible things in the Status column and want to sum 6 of them, you can add an OR function to the criteria and list the 6 that you want to include like this:

    =SUMIFS(Value:Value, Owners:Owners, "Mickey", Status:Status, OR(@cell = "Testing", @cell = "Not started", @cell = "Requirements capture", @cell = "Completed", @cell = "In development", @cell = "Billing"))
    

    In my example, this would return 255,703.

    Alternatively, you could write a shorter formula to count rows where the status is not the 2 you don't want.

    =SUMIFS(Value:Value, Owners:Owners, "Mickey", Status:Status, AND(@cell <> "Cancelled", @cell <> "On Hold"))
    

    In my example, this would still return 255,703.

  • Thank you so much

    I used the final shorter formula version

    Appreciate you getting me there after days of frustation

  • KPH
    KPH ✭✭✭✭✭✭

    Great news, glad I could help.

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