Combining "IF" formulas with "IFERROR" formulas
I am attempting to return a simple YES or NO if a company I have is in another sheet. I created a match formula in one column and in the adjacent column, I was hoping to do a simple IF statement to return the appropriate results. Due to the companies which did not return a match being populated with a #NO MATCH error, I am unable to use the simple IF statement. I then attempted to use a layered IF statement with the second function being an IF ERROR formula. I am having issues with that as well. My formula is below. Please let me know if I am missing something.
=IF([Match Formula]2 > 0.5, "Yes", IFERROR([Match Formula]2, "No"))
Best Answer
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There are two different options. The first one is wrapping the IF statement in the IFERROR.
.
=IFERROR(IF([Match Formula]2 > .5, "Yes"), "No")
.
If that doesn't work, could you post your MATCH formula?
Come see me in Seattle at ENGAGE 2024! I will be at the 10xViz partner booth throughout as well as the "Lets Talk About Community" Meet & Eat table on Tuesday from 11:45am - 12:45pm!
Answers
-
There are two different options. The first one is wrapping the IF statement in the IFERROR.
.
=IFERROR(IF([Match Formula]2 > .5, "Yes"), "No")
.
If that doesn't work, could you post your MATCH formula?
Come see me in Seattle at ENGAGE 2024! I will be at the 10xViz partner booth throughout as well as the "Lets Talk About Community" Meet & Eat table on Tuesday from 11:45am - 12:45pm!
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I would probably use the ISERROR() function in this case because you're checking the result of a calculation. Then I would wrap that with the IF() function. Something like:
=IF(ISERROR([Match Formula]2),"No", "Yes")
Might something like that work?
-Jeremy
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This worked perfect thanks!
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This worked perfectly as well
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Happy to help!
Come see me in Seattle at ENGAGE 2024! I will be at the 10xViz partner booth throughout as well as the "Lets Talk About Community" Meet & Eat table on Tuesday from 11:45am - 12:45pm!
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