Hello, I am trying to use the following formula to remove illegal characters from a string (situated in column "name"), but it fails as unparsable. Can anyone tell me why? Is there a limit I've gone over?
I note that the formula is trying to use the brackets (parentheses in USA) even though they are enclosed in quotation marks. However, even if I reduce the formula by 2 nests to get rid of these from the formula, it still fails.
The formula used to work in removing spaces and full stops (periods), but in this "enhanced" version, it doesn't work any more.
Any suggestions?
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(name2, " ", ""), "'", ""), "`", ""), "(", ""), ")", ""), "[", ""), "]", ""), "-", ""), ".", ""), ",", ""), ":", ""), "&", ""), """, ""), "*", ""), "/", "")