Formula If/Then help
I have the following columns
 Confidence
 2023 Calendar Savings
I need to have a formula in a third column that calculates the following
If confidence = 25 then multiply 2023 Calendar Savings by .25
Answers

HI @Lisa Welch
This should do the trick for you.
=if(Confidence@row=25,[2023 Calendar Savings]@row*.25,0)
Hope that helps
Thanks
Paul

Hi Paul,
I got an #unparseable?

@Lisa Welch Double check that the column names match exactly what is being used in your sheet.

Hi Paul  yes, I have it matching but still receiving unparseable? The result would be in 2023 Calendar Adjusted at Confidence column. Here's a screenshot.
If Confidence % is 25 multiply 2023 Calendar Savings by .25 then if Confidence % is 50 multiply 2023 Calendar Savings by .50 then if Confidence % is 75 multiply 2023 Calendar Savings by .75 then if Confidence % is 100 multiply 2023 Calendar Savings by 1.

It looks like the Confidence@row needs to be changed to [Confidence %]@row to match what you have in the sheet.

Hi Paul  Here's the exact formula, but still receiving unparseable


Thanks Paul...That did it!
Now, how do I string together in ONE formula?
=IF([Confidence %]@row = 25, [2023 Calendar Savings]@row * 0.25, 0)
=IF([Confidence %]@row = 50, [2023 Calendar Savings]@row * 0.5, 0)
=IF([Confidence %]@row = 75, [2023 Calendar Savings]@row * 0.75, 0)
=IF([Confidence %]@row = 100, [2023 Calendar Savings]@row * 1, 0)

You would drop the second one where you have the first zero. Then drop the third in place of the second's zero. Then the fourth in place of the third's zero.
=IF(........, ..........., IF(..........., ............., IF(..........., ..........., IF(............, .............., 0))))

Thank you Paul. I'm all set. Greatly appreciate the help.

Help Article Resources
Categories
Check out the Formula Handbook template!