Formula If/Then help

Lisa Welch

I have the following columns

1. Confidence
2. 2023 Calendar Savings

I need to have a formula in a third column that calculates the following

If confidence = 25 then multiply 2023 Calendar Savings by .25

Paul McGuinness

HI @Lisa Welch

This should do the trick for you.

=if(Confidence@row=25,[2023 Calendar Savings]@row*.25,0)

Hope that helps

Thanks

Paul

Lisa Welch

Hi Paul,

I got an #unparseable?

Paul Newcome

@Lisa Welch Double check that the column names match exactly what is being used in your sheet.

Lisa Welch

Hi Paul - yes, I have it matching but still receiving unparseable? The result would be in 2023 Calendar Adjusted at Confidence column. Here's a screenshot.

If Confidence % is 25 multiply 2023 Calendar Savings by .25 then if Confidence % is 50 multiply 2023 Calendar Savings by .50 then if Confidence % is 75 multiply 2023 Calendar Savings by .75 then if Confidence % is 100 multiply 2023 Calendar Savings by 1.

Paul Newcome

It looks like the Confidence@row needs to be changed to [Confidence %]@row to match what you have in the sheet.

Lisa Welch

Hi Paul - Here's the exact formula, but still receiving unparseable

Paul Newcome

Try a space before the % to match your column name.

Lisa Welch

Thanks Paul...That did it!

Now, how do I string together in ONE formula?

=IF([Confidence %]@row = 25, [2023 Calendar Savings]@row * 0.25, 0)

=IF([Confidence %]@row = 50, [2023 Calendar Savings]@row * 0.5, 0)

=IF([Confidence %]@row = 75, [2023 Calendar Savings]@row * 0.75, 0)

=IF([Confidence %]@row = 100, [2023 Calendar Savings]@row * 1, 0)

Paul Newcome

You would drop the second one where you have the first zero. Then drop the third in place of the second's zero. Then the fourth in place of the third's zero.

=IF(........, ..........., IF(..........., ............., IF(..........., ..........., IF(............, .............., 0))))

Lisa Welch

Thank you Paul. I'm all set. Greatly appreciate the help.

Paul Newcome

Happy to help. 👍️