Formula for average between 2 dates

Hi all,
Probably a very stupid question, but is there a formula that presents the average date between 2 dates. For example, the average date between Monday 4th Septmeber and Wednesday 6th September should be '5th September'
Best Answer
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Hi @Jef Snyders,
The AVG function will do this for you. If on one row you would use:
=AVG([1st date]@row, [2nd date]@row)
If you were wanting to do it without any cell references, then you would use AVG & DATE (using your example):
=AVG(DATE(2023,9,4), DATE(2023,9,6))
Hope this helps, but if you've any questions or problems then just post! π
Answers
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Hi @Jef Snyders,
The AVG function will do this for you. If on one row you would use:
=AVG([1st date]@row, [2nd date]@row)
If you were wanting to do it without any cell references, then you would use AVG & DATE (using your example):
=AVG(DATE(2023,9,4), DATE(2023,9,6))
Hope this helps, but if you've any questions or problems then just post! π
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Hi Jef Snyders,
By the way, it's quite an interesting question!
You just need a helper column βAverageβ with the formula -
=([Date2]@row - [Date1]@row) / 2
Where Date2 and Date1 are date columns having different dates.
Apply the below formula in the βAverage Dateβ column whose column type is a date.
=[Date1]@row + Average@row
This is how you will get the average date between two dates!
Thank you,
Shubham Umale
Associate - Smartsheet, Ignatiuz Software
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Thanks @Nick Korna - I was afraid that this was not going to work as I received this message.
But I should just click on 'allow' and it seems to be ok!
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Hi @Shubham , thanks for your quick response.
Your solution works as well. But apparently the helper column is not needed as just '=avg' function does work. Any reason why you suggest the helper column?
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The message is just from the header being set to only allow dates (handy to stop people accidentally entering the wrong thing/making a typo):
Of course, this usually stops people entering formulas as well, but as sheet admin you're able to overwrite this as you found! π
Glad this helped solve your question though! π
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